Category: Python Solutions

Project Euler 15 (Python)

Question 15 from Project Euler:

Starting in the top left corner of a 2 by 2 grid, there are 6 routes (without backtracking) to the bottom right corner.

How many routes are there through a 20 by 20 grid?

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import time
start = time.time()
 
#2x2 square takes 4 steps to reach the end
#so a 20x20 takes 40 steps
#solve mathematically with 40 choose 20
x = y = 1
for i in range(1, 41):
    x = x * i
for i in range(1, 21):
    y = y * i
print x/y/y
 
print time.time()-start

Project Euler 14 (Python)

Question 14 from Project Euler:

The following iterative sequence is defined for the set of positive integers:

n -> n/2 (n is even)
n -> 3n + 1 (n is odd)

Using the rule above and starting with 13, we generate the following sequence:
13, 40, 20, 10, 5, 16, 8, 4, 2, 1
It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1.

Which starting number, under one million, produces the longest chain?
NOTE: Once the chain starts the terms are allowed to go above one million.

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import time
start = time.time()
 
def nextSequence(n):
    #implement rules as laid out in question
    if n%2 == 0:
        return n/2
    else:
        return (n*3)+1
 
#loop through required range
#then loop back down to 1 using nextSequence
chains = [0,1]
for i in range(2,1000000):
    j = i
    x = 0
    while j > 1:
        j = nextSequence(j)
        #check if we have already visited this number
        #if so we already have the chain from this point
        if j < len(chains):
            x += chains[j]
            break
        x += 1
    chains.append(x)
 
print chains.index(max(chains))
 
print time.time()-start

Project Euler 13 (Python)

Question 13 from Project Euler:

Work out the first ten digits of the sum of the following one-hundred 50-digit numbers.

37107287533902102798797998220837590246510135740250
…full list shown in the code…
53503534226472524250874054075591789781264330331690

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import time
start = time.time()
 
#set the numbers as a string so we can use string methods and operators
numStr = '\
37107287533902102798797998220837590246510135740250\
46376937677490009712648124896970078050417018260538\
74324986199524741059474233309513058123726617309629\
91942213363574161572522430563301811072406154908250\
23067588207539346171171980310421047513778063246676\
89261670696623633820136378418383684178734361726757\
28112879812849979408065481931592621691275889832738\
44274228917432520321923589422876796487670272189318\
47451445736001306439091167216856844588711603153276\
70386486105843025439939619828917593665686757934951\
62176457141856560629502157223196586755079324193331\
64906352462741904929101432445813822663347944758178\
92575867718337217661963751590579239728245598838407\
58203565325359399008402633568948830189458628227828\
80181199384826282014278194139940567587151170094390\
35398664372827112653829987240784473053190104293586\
86515506006295864861532075273371959191420517255829\
71693888707715466499115593487603532921714970056938\
54370070576826684624621495650076471787294438377604\
53282654108756828443191190634694037855217779295145\
36123272525000296071075082563815656710885258350721\
45876576172410976447339110607218265236877223636045\
17423706905851860660448207621209813287860733969412\
81142660418086830619328460811191061556940512689692\
51934325451728388641918047049293215058642563049483\
62467221648435076201727918039944693004732956340691\
15732444386908125794514089057706229429197107928209\
55037687525678773091862540744969844508330393682126\
18336384825330154686196124348767681297534375946515\
80386287592878490201521685554828717201219257766954\
78182833757993103614740356856449095527097864797581\
16726320100436897842553539920931837441497806860984\
48403098129077791799088218795327364475675590848030\
87086987551392711854517078544161852424320693150332\
59959406895756536782107074926966537676326235447210\
69793950679652694742597709739166693763042633987085\
41052684708299085211399427365734116182760315001271\
65378607361501080857009149939512557028198746004375\
35829035317434717326932123578154982629742552737307\
94953759765105305946966067683156574377167401875275\
88902802571733229619176668713819931811048770190271\
25267680276078003013678680992525463401061632866526\
36270218540497705585629946580636237993140746255962\
24074486908231174977792365466257246923322810917141\
91430288197103288597806669760892938638285025333403\
34413065578016127815921815005561868836468420090470\
23053081172816430487623791969842487255036638784583\
11487696932154902810424020138335124462181441773470\
63783299490636259666498587618221225225512486764533\
67720186971698544312419572409913959008952310058822\
95548255300263520781532296796249481641953868218774\
76085327132285723110424803456124867697064507995236\
37774242535411291684276865538926205024910326572967\
23701913275725675285653248258265463092207058596522\
29798860272258331913126375147341994889534765745501\
18495701454879288984856827726077713721403798879715\
38298203783031473527721580348144513491373226651381\
34829543829199918180278916522431027392251122869539\
40957953066405232632538044100059654939159879593635\
29746152185502371307642255121183693803580388584903\
41698116222072977186158236678424689157993532961922\
62467957194401269043877107275048102390895523597457\
23189706772547915061505504953922979530901129967519\
86188088225875314529584099251203829009407770775672\
11306739708304724483816533873502340845647058077308\
82959174767140363198008187129011875491310547126581\
97623331044818386269515456334926366572897563400500\
42846280183517070527831839425882145521227251250327\
55121603546981200581762165212827652751691296897789\
32238195734329339946437501907836945765883352399886\
75506164965184775180738168837861091527357929701337\
62177842752192623401942399639168044983993173312731\
32924185707147349566916674687634660915035914677504\
99518671430235219628894890102423325116913619626622\
73267460800591547471830798392868535206946944540724\
76841822524674417161514036427982273348055556214818\
97142617910342598647204516893989422179826088076852\
87783646182799346313767754307809363333018982642090\
10848802521674670883215120185883543223812876952786\
71329612474782464538636993009049310363619763878039\
62184073572399794223406235393808339651327408011116\
66627891981488087797941876876144230030984490851411\
60661826293682836764744779239180335110989069790714\
85786944089552990653640447425576083659976645795096\
66024396409905389607120198219976047599490197230297\
64913982680032973156037120041377903785566085089252\
16730939319872750275468906903707539413042652315011\
94809377245048795150954100921645863754710598436791\
78639167021187492431995700641917969777599028300699\
15368713711936614952811305876380278410754449733078\
40789923115535562561142322423255033685442488917353\
44889911501440648020369068063960672322193204149535\
41503128880339536053299340368006977710650566631954\
81234880673210146739058568557934581403627822703280\
82616570773948327592232845941706525094512325230608\
22918802058777319719839450180888072429661980811197\
77158542502016545090413245809786882778948721859617\
72107838435069186155435662884062257473692284509516\
20849603980134001723930671666823555245252804609722\
53503534226472524250874054075591789781264330331690'
 
#loop through string one 50-digit number at a time and add it to total
x = 0
for i in range(0, 4999, 50):
    x += int(numStr[i:i+49])
 
#convert to string and print first 10 chars
print str(x)[:10]
 
print time.time()-start

Project Euler 12 (Python)

Question 12 from Project Euler:

The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, …

Let us list the factors of the first seven triangle numbers:
1: 1
3: 1,3
6: 1,2,3,6
10: 1,2,5,10
15: 1,3,5,15
21: 1,3,7,21
28: 1,2,4,7,14,28
We can see that 28 is the first triangle number to have over five divisors.

What is the value of the first triangle number to have over five hundred divisors?

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import time
start = time.time()
 
def countFactors(n=3, c=2):
    #loop to square root, test with modulus, check for squares
    for i in range(2, int(n**0.5)+1):
        if n%i == 0:
            if i != int(n**0.5)+1:
                c+=2
            else:
                c+=1
    return c
 
def triangleNumbers(i=1):
    #generate triangle numbers with 0.5*n*n1
    while True:
        yield int(0.5*i*(i+1))
        i+=1
 
#loop and a half, generate triangle numbers and count factors
triNums = triangleNumbers()
while True:
    n = triNums.next()
    if countFactors(n) > 500:
        print n
        break
 
print time.time()-start

Project Euler 11 (Python)

Question 11 from Project Euler:

08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48

What is the greatest product of four adjacent numbers in any direction (up, down, left, right, or diagonally) in the 20×20 grid?

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import time
start = time.time()
 
#build the grid
grid = [[8,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,8],
[49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00],
[81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65],
[52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91],
[22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80],
[24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50],
[32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70],
[67,26,20,68,02,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21],
[24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72],
[21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95],
[78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,9,53,56,92],
[16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57],
[86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58],
[19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40],
[04,52,8,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66],
[88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69],
[04,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36],
[20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16],
[20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54],
[01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48]]
 
highScore = 0
product = 0
 
#use nested loops and offsets to work out products
 
#horizontal
for i in range(17):
    for j in range(20):
        product = grid[j][i] * grid[j][i+1] * grid[j][i+2] * grid[j][i+3]
        if product > highScore:
            highScore = product
 
#vertical
for i in range(20):
    for j in range(17):
        product = grid[j][i] * grid[j+1][i] * grid[j+2][i] * grid[j+3][i]
        if product > highScore:
            highScore = product
 
#left diagonal
for i in range(17):
    for j in range(17):
        product = grid[j][i+3] * grid[j+1][i+2] * grid[j+2][i+1] * grid[j+3][i]
        if product > highScore:
            highScore = product
 
#right diagonal
for i in range(17):
    for j in range(17):
        product = grid[j][i] * grid[j+1][i+1] * grid[j+2][i+2] * grid[j+2][i+2]
        if product > highScore:
            highScore = product
 
print highScore
 
print time.time()-start

Project Euler 10 (Python)

Question 10 from Project Euler:

The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17.

Find the sum of all the primes below two million.

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import time
start = time.time()
 
#solve with the Sieve of Eratosthenes
target = 2000000
sieve= range(target+1)
for i in range(2, (int(target**0.5)+1)):
    if sieve[i]:
	for j in range(i**2, target+1, i):
            sieve[j] = 0
 
print sum(sieve)-1
 
print time.time()-start

Project Euler 9 (Python)

Question 9 from Project Euler:

A Pythagorean triplet is a set of three natural numbers, a < b < c, for which, a2 + b2 = c2 For example, 32 + 42 = 9 + 16 = 25 = 52.

There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.

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import time
start = time.time()
 
#solve with Euclid's formula
def eulerNine(target):
    for m in range(1,target):
        for n in range(1,m):
            a = m**2-n**2
            b = 2*m*n
            c = m**2+n**2
            if a+b+c == target:
                return a*b*c
print eulerNine(1000)
 
print time.time()-start

Project Euler 8 (Python)

Question 8 from Project Euler:

Find the greatest product of five consecutive digits in the 1000-digit number.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

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import time
start = time.time()
 
def productsByFives(nStr, offset=0, highScore=0):
    if offset+5 > len(nStr):
        #end of string reached
        return highScore
    #use offsets to get product and compare to running highscore
    product = int(nStr[offset])*int(nStr[offset+1])*int(nStr[offset+2])*int(nStr[offset+3])*int(nStr[offset+4])
    if product > highScore:
        highScore = product
    #call function again with offset incremented
    return productsByFives(nStr, offset+1, highScore)
 
#set number as string so we can use string methods and operators
nStr = '7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450'
 
print productsByFives(nStr)
 
print time.time()-start

Project Euler 7 (Python)

Question 7 from Project Euler:

By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13.

What is the 10001st prime number?

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import time
start = time.time()
 
def isPrime(n):
    #using trial division
    n = abs(int(n))
    if n < 2:
        return False
    if n == 2:
        return True
    if not n & 1:
        return False
    for x in range(3, int(n**0.5)+1, 2):
        if n % x == 0:
            return False
    return True
 
target = 10001
#one var to track primes
#one to increment numbers to test
primes = i = 0
while primes < target:
    i += 1
    if isPrime(i):
        primes += 1
 
print i
 
print time.time()-start

Project Euler 6 (Python)

Question 6 from Project Euler:

The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 – 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

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import time
start = time.time()
 
n = 100
print (sum(range(1,n+1))**2) - (sum(x*x for x in range(1,n+1)))
 
print time.time()-start